5w2+10w=40

Solution for 5w2+10w=40 equation:

5w^2+10w=40

We move all terms to the left:

5w^2+10w-(40)=0

a = 5; b = 10; c = -40;
Δ = b2-4ac
Δ = 102-4·5·(-40)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-30}{2*5}=\frac{-40}{10}
=-4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+30}{2*5}=\frac{20}{10}
=2
$