5w2+13w+7=0

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Solution for 5w2+13w+7=0 equation: 



5w^2+13w+7=0

a = 5; b = 13; c = +7;
Δ = b2-4ac
Δ = 132-4·5·7
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{29}}{2*5}=\frac{-13-\sqrt{29}}{10}
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{29}}{2*5}=\frac{-13+\sqrt{29}}{10}
$

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