5w2-23w-42=0

Solution for 5w2-23w-42=0 equation:

5w^2-23w-42=0

a = 5; b = -23; c = -42;
Δ = b2-4ac
Δ = -232-4·5·(-42)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-37}{2*5}=\frac{-14}{10}
=-1+2/5
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+37}{2*5}=\frac{60}{10}
=6
$