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5x(-1x+11)=5x-7x(x-7)
We move all terms to the left:
5x(-1x+11)-(5x-7x(x-7))=0
We multiply parentheses
-5x^2+55x-(5x-7x(x-7))=0
We calculate terms in parentheses: -(5x-7x(x-7)), so:We get rid of parentheses
5x-7x(x-7)
We multiply parentheses
-7x^2+5x+49x
We add all the numbers together, and all the variables
-7x^2+54x
Back to the equation:
-(-7x^2+54x)
-5x^2+7x^2-54x+55x=0
We add all the numbers together, and all the variables
2x^2+x=0
a = 2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·2·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*2}=\frac{-2}{4} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*2}=\frac{0}{4} =0 $
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