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5x(-3x)-6x=-1
We move all terms to the left:
5x(-3x)-6x-(-1)=0
We add all the numbers together, and all the variables
-6x+5x(-3x)+1=0
We multiply parentheses
-15x^2-6x+1=0
a = -15; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-15)·1
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{6}}{2*-15}=\frac{6-4\sqrt{6}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{6}}{2*-15}=\frac{6+4\sqrt{6}}{-30} $
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