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5x(-3x+4)=
We move all terms to the left:
5x(-3x+4)-()=0
We add all the numbers together, and all the variables
5x(-3x+4)=0
We multiply parentheses
-15x^2+20x=0
a = -15; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-15)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-15}=\frac{-40}{-30} =1+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-15}=\frac{0}{-30} =0 $
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