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5x(10/11)=9
We move all terms to the left:
5x(10/11)-(9)=0
We add all the numbers together, and all the variables
5x(+10/11)-9=0
We multiply parentheses
50x^2-9=0
a = 50; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·50·(-9)
Δ = 1800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1800}=\sqrt{900*2}=\sqrt{900}*\sqrt{2}=30\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30\sqrt{2}}{2*50}=\frac{0-30\sqrt{2}}{100} =-\frac{30\sqrt{2}}{100} =-\frac{3\sqrt{2}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30\sqrt{2}}{2*50}=\frac{0+30\sqrt{2}}{100} =\frac{30\sqrt{2}}{100} =\frac{3\sqrt{2}}{10} $
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