5x(2-4x)+8=16x

Solution for 5x(2-4x)+8=16x equation:

5x(2-4x)+8=16x

We move all terms to the left:

5x(2-4x)+8-(16x)=0

We add all the numbers together, and all the variables

5x(-4x+2)-16x+8=0

We add all the numbers together, and all the variables

-16x+5x(-4x+2)+8=0

We multiply parentheses

-20x^2-16x+10x+8=0

We add all the numbers together, and all the variables

-20x^2-6x+8=0

a = -20; b = -6; c = +8;
Δ = b2-4ac
Δ = -62-4·(-20)·8
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-26}{2*-20}=\frac{-20}{-40}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+26}{2*-20}=\frac{32}{-40}
=-4/5
$