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5x(2-x)=20
We move all terms to the left:
5x(2-x)-(20)=0
We add all the numbers together, and all the variables
5x(-1x+2)-20=0
We multiply parentheses
-5x^2+10x-20=0
a = -5; b = 10; c = -20;
Δ = b2-4ac
Δ = 102-4·(-5)·(-20)
Δ = -300
Delta is less than zero, so there is no solution for the equation
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