5x(2x-14)=0

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Solution for 5x(2x-14)=0 equation:



5x(2x-14)=0
We multiply parentheses
10x^2-70x=0
a = 10; b = -70; c = 0;
Δ = b2-4ac
Δ = -702-4·10·0
Δ = 4900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4900}=70$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-70}{2*10}=\frac{0}{20} =0 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+70}{2*10}=\frac{140}{20} =7 $

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