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5x(2x-3)-2x(x-4)=3+3
We move all terms to the left:
5x(2x-3)-2x(x-4)-(3+3)=0
We add all the numbers together, and all the variables
5x(2x-3)-2x(x-4)-6=0
We multiply parentheses
10x^2-2x^2-15x+8x-6=0
We add all the numbers together, and all the variables
8x^2-7x-6=0
a = 8; b = -7; c = -6;
Δ = b2-4ac
Δ = -72-4·8·(-6)
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{241}}{2*8}=\frac{7-\sqrt{241}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{241}}{2*8}=\frac{7+\sqrt{241}}{16} $
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