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5x(3+7x)=2
We move all terms to the left:
5x(3+7x)-(2)=0
We add all the numbers together, and all the variables
5x(7x+3)-2=0
We multiply parentheses
35x^2+15x-2=0
a = 35; b = 15; c = -2;
Δ = b2-4ac
Δ = 152-4·35·(-2)
Δ = 505
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{505}}{2*35}=\frac{-15-\sqrt{505}}{70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{505}}{2*35}=\frac{-15+\sqrt{505}}{70} $
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