5x(3x+2)=600

Solution for 5x(3x+2)=600 equation:

5x(3x+2)=600

We move all terms to the left:

5x(3x+2)-(600)=0

We multiply parentheses

15x^2+10x-600=0

a = 15; b = 10; c = -600;
Δ = b2-4ac
Δ = 102-4·15·(-600)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36100}=190$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-190}{2*15}=\frac{-200}{30}
=-6+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+190}{2*15}=\frac{180}{30}
=6
$