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5x(3x+8)+2=5
We move all terms to the left:
5x(3x+8)+2-(5)=0
We add all the numbers together, and all the variables
5x(3x+8)-3=0
We multiply parentheses
15x^2+40x-3=0
a = 15; b = 40; c = -3;
Δ = b2-4ac
Δ = 402-4·15·(-3)
Δ = 1780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1780}=\sqrt{4*445}=\sqrt{4}*\sqrt{445}=2\sqrt{445}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-2\sqrt{445}}{2*15}=\frac{-40-2\sqrt{445}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+2\sqrt{445}}{2*15}=\frac{-40+2\sqrt{445}}{30} $
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