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5x(3x-12)=30
We move all terms to the left:
5x(3x-12)-(30)=0
We multiply parentheses
15x^2-60x-30=0
a = 15; b = -60; c = -30;
Δ = b2-4ac
Δ = -602-4·15·(-30)
Δ = 5400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5400}=\sqrt{900*6}=\sqrt{900}*\sqrt{6}=30\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-30\sqrt{6}}{2*15}=\frac{60-30\sqrt{6}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+30\sqrt{6}}{2*15}=\frac{60+30\sqrt{6}}{30} $
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