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5x(3x-2)=5
We move all terms to the left:
5x(3x-2)-(5)=0
We multiply parentheses
15x^2-10x-5=0
a = 15; b = -10; c = -5;
Δ = b2-4ac
Δ = -102-4·15·(-5)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-20}{2*15}=\frac{-10}{30} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+20}{2*15}=\frac{30}{30} =1 $
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