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5x(4x+12)=180
We move all terms to the left:
5x(4x+12)-(180)=0
We multiply parentheses
20x^2+60x-180=0
a = 20; b = 60; c = -180;
Δ = b2-4ac
Δ = 602-4·20·(-180)
Δ = 18000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{18000}=\sqrt{3600*5}=\sqrt{3600}*\sqrt{5}=60\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60\sqrt{5}}{2*20}=\frac{-60-60\sqrt{5}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60\sqrt{5}}{2*20}=\frac{-60+60\sqrt{5}}{40} $
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