5x(4y+3x)=5x(3x+4y)

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Solution for 5x(4y+3x)=5x(3x+4y) equation: 


Simplifying
5x(4y + 3x) = 5x(3x + 4y)

Reorder the terms:
5x(3x + 4y) = 5x(3x + 4y)
(3x * 5x + 4y * 5x) = 5x(3x + 4y)

Reorder the terms:
(20xy + 15x2) = 5x(3x + 4y)
(20xy + 15x2) = 5x(3x + 4y)
20xy + 15x2 = (3x * 5x + 4y * 5x)

Reorder the terms:
20xy + 15x2 = (20xy + 15x2)
20xy + 15x2 = (20xy + 15x2)

Add '-20xy' to each side of the equation.
20xy + -20xy + 15x2 = 20xy + -20xy + 15x2

Combine like terms: 20xy + -20xy = 0
0 + 15x2 = 20xy + -20xy + 15x2
15x2 = 20xy + -20xy + 15x2

Combine like terms: 20xy + -20xy = 0
15x2 = 0 + 15x2
15x2 = 15x2

Add '-15x2' to each side of the equation.
15x2 + -15x2 = 15x2 + -15x2

Combine like terms: 15x2 + -15x2 = 0
0 = 15x2 + -15x2

Combine like terms: 15x2 + -15x2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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