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5x(5x+60)=360
We move all terms to the left:
5x(5x+60)-(360)=0
We multiply parentheses
25x^2+300x-360=0
a = 25; b = 300; c = -360;
Δ = b2-4ac
Δ = 3002-4·25·(-360)
Δ = 126000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{126000}=\sqrt{3600*35}=\sqrt{3600}*\sqrt{35}=60\sqrt{35}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-60\sqrt{35}}{2*25}=\frac{-300-60\sqrt{35}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+60\sqrt{35}}{2*25}=\frac{-300+60\sqrt{35}}{50} $
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