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5x(6x+3)+3x(4x+4)=6x(7x+3)+3(2x+13)
We move all terms to the left:
5x(6x+3)+3x(4x+4)-(6x(7x+3)+3(2x+13))=0
We multiply parentheses
30x^2+12x^2+15x+12x-(6x(7x+3)+3(2x+13))=0
We calculate terms in parentheses: -(6x(7x+3)+3(2x+13)), so:We add all the numbers together, and all the variables
6x(7x+3)+3(2x+13)
We multiply parentheses
42x^2+18x+6x+39
We add all the numbers together, and all the variables
42x^2+24x+39
Back to the equation:
-(42x^2+24x+39)
42x^2+27x-(42x^2+24x+39)=0
We get rid of parentheses
42x^2-42x^2+27x-24x-39=0
We add all the numbers together, and all the variables
3x-39=0
We move all terms containing x to the left, all other terms to the right
3x=39
x=39/3
x=13
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