5x(8x-11)=(2x+6)

Solution for 5x(8x-11)=(2x+6) equation:

5x(8x-11)=(2x+6)

We move all terms to the left:

5x(8x-11)-((2x+6))=0

We multiply parentheses

40x^2-55x-((2x+6))=0


We calculate terms in parentheses: -((2x+6)), so:

(2x+6)

We get rid of parentheses

2x+6

Back to the equation:

-(2x+6)


We get rid of parentheses

40x^2-55x-2x-6=0

We add all the numbers together, and all the variables

40x^2-57x-6=0

a = 40; b = -57; c = -6;
Δ = b2-4ac
Δ = -572-4·40·(-6)
Δ = 4209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-57)-\sqrt{4209}}{2*40}=\frac{57-\sqrt{4209}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-57)+\sqrt{4209}}{2*40}=\frac{57+\sqrt{4209}}{80}
$