5x(x+18)(x-18)=0

Solution for 5x(x+18)(x-18)=0 equation:

5x(x+18)(x-18)=0

We use the square of the difference formula

x^2-324=0

a = 1; b = 0; c = -324;
Δ = b2-4ac
Δ = 02-4·1·(-324)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*1}=\frac{-36}{2}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*1}=\frac{36}{2}
=18
$