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5x(x+2)-3x(x+6)=40
We move all terms to the left:
5x(x+2)-3x(x+6)-(40)=0
We multiply parentheses
5x^2-3x^2+10x-18x-40=0
We add all the numbers together, and all the variables
2x^2-8x-40=0
a = 2; b = -8; c = -40;
Δ = b2-4ac
Δ = -82-4·2·(-40)
Δ = 384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{384}=\sqrt{64*6}=\sqrt{64}*\sqrt{6}=8\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8\sqrt{6}}{2*2}=\frac{8-8\sqrt{6}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8\sqrt{6}}{2*2}=\frac{8+8\sqrt{6}}{4} $
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