5x(x+2)=(5x-1)(x+1)

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Solution for 5x(x+2)=(5x-1)(x+1) equation:



5x(x+2)=(5x-1)(x+1)
We move all terms to the left:
5x(x+2)-((5x-1)(x+1))=0
We multiply parentheses
5x^2+10x-((5x-1)(x+1))=0
We multiply parentheses ..
5x^2-((+5x^2+5x-1x-1))+10x=0
We calculate terms in parentheses: -((+5x^2+5x-1x-1)), so:
(+5x^2+5x-1x-1)
We get rid of parentheses
5x^2+5x-1x-1
We add all the numbers together, and all the variables
5x^2+4x-1
Back to the equation:
-(5x^2+4x-1)
We add all the numbers together, and all the variables
5x^2+10x-(5x^2+4x-1)=0
We get rid of parentheses
5x^2-5x^2+10x-4x+1=0
We add all the numbers together, and all the variables
6x+1=0
We move all terms containing x to the left, all other terms to the right
6x=-1
x=-1/6
x=-1/6

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