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5x(x+2)=3(x+8)
We move all terms to the left:
5x(x+2)-(3(x+8))=0
We multiply parentheses
5x^2+10x-(3(x+8))=0
We calculate terms in parentheses: -(3(x+8)), so:We get rid of parentheses
3(x+8)
We multiply parentheses
3x+24
Back to the equation:
-(3x+24)
5x^2+10x-3x-24=0
We add all the numbers together, and all the variables
5x^2+7x-24=0
a = 5; b = 7; c = -24;
Δ = b2-4ac
Δ = 72-4·5·(-24)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*5}=\frac{-30}{10} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*5}=\frac{16}{10} =1+3/5 $
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