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Simplifying 5x(x + 3) = (x)(5x + -3) + 36forx Reorder the terms: 5x(3 + x) = (x)(5x + -3) + 36forx (3 * 5x + x * 5x) = (x)(5x + -3) + 36forx (15x + 5x2) = (x)(5x + -3) + 36forx Reorder the terms: 15x + 5x2 = x(-3 + 5x) + 36forx 15x + 5x2 = (-3 * x + 5x * x) + 36forx 15x + 5x2 = (-3x + 5x2) + 36forx Reorder the terms: 15x + 5x2 = 36forx + -3x + 5x2 Add '-5x2' to each side of the equation. 15x + 5x2 + -5x2 = 36forx + -3x + 5x2 + -5x2 Combine like terms: 5x2 + -5x2 = 0 15x + 0 = 36forx + -3x + 5x2 + -5x2 15x = 36forx + -3x + 5x2 + -5x2 Combine like terms: 5x2 + -5x2 = 0 15x = 36forx + -3x + 0 15x = 36forx + -3x Solving 15x = 36forx + -3x Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-36forx' to each side of the equation. -36forx + 15x = 36forx + -36forx + -3x Combine like terms: 36forx + -36forx = 0 -36forx + 15x = 0 + -3x -36forx + 15x = -3x Add '3x' to each side of the equation. -36forx + 15x + 3x = -3x + 3x Combine like terms: 15x + 3x = 18x -36forx + 18x = -3x + 3x Combine like terms: -3x + 3x = 0 -36forx + 18x = 0 Factor out the Greatest Common Factor (GCF), '18x'. 18x(-2for + 1) = 0 Ignore the factor 18.Subproblem 1
Set the factor 'x' equal to zero and attempt to solve: Simplifying x = 0 Solving x = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x = 0Subproblem 2
Set the factor '(-2for + 1)' equal to zero and attempt to solve: Simplifying -2for + 1 = 0 Reorder the terms: 1 + -2for = 0 Solving 1 + -2for = 0 Move all terms containing x to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -2for = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -2for = 0 + -1 -2for = 0 + -1 Combine like terms: 0 + -1 = -1 -2for = -1 Add '2for' to each side of the equation. -2for + 2for = -1 + 2for Combine like terms: -2for + 2for = 0 0 = -1 + 2for Simplifying 0 = -1 + 2for The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Solution
x = {0}
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