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5x(x+40)=180
We move all terms to the left:
5x(x+40)-(180)=0
We multiply parentheses
5x^2+200x-180=0
a = 5; b = 200; c = -180;
Δ = b2-4ac
Δ = 2002-4·5·(-180)
Δ = 43600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{43600}=\sqrt{400*109}=\sqrt{400}*\sqrt{109}=20\sqrt{109}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(200)-20\sqrt{109}}{2*5}=\frac{-200-20\sqrt{109}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(200)+20\sqrt{109}}{2*5}=\frac{-200+20\sqrt{109}}{10} $
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