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5x(x+6)=7
We move all terms to the left:
5x(x+6)-(7)=0
We multiply parentheses
5x^2+30x-7=0
a = 5; b = 30; c = -7;
Δ = b2-4ac
Δ = 302-4·5·(-7)
Δ = 1040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1040}=\sqrt{16*65}=\sqrt{16}*\sqrt{65}=4\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-4\sqrt{65}}{2*5}=\frac{-30-4\sqrt{65}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+4\sqrt{65}}{2*5}=\frac{-30+4\sqrt{65}}{10} $
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