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5x(x+8)=35
We move all terms to the left:
5x(x+8)-(35)=0
We multiply parentheses
5x^2+40x-35=0
a = 5; b = 40; c = -35;
Δ = b2-4ac
Δ = 402-4·5·(-35)
Δ = 2300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2300}=\sqrt{100*23}=\sqrt{100}*\sqrt{23}=10\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-10\sqrt{23}}{2*5}=\frac{-40-10\sqrt{23}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+10\sqrt{23}}{2*5}=\frac{-40+10\sqrt{23}}{10} $
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