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5x(x+9)+4x=5
We move all terms to the left:
5x(x+9)+4x-(5)=0
We add all the numbers together, and all the variables
4x+5x(x+9)-5=0
We multiply parentheses
5x^2+4x+45x-5=0
We add all the numbers together, and all the variables
5x^2+49x-5=0
a = 5; b = 49; c = -5;
Δ = b2-4ac
Δ = 492-4·5·(-5)
Δ = 2501
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{2501}}{2*5}=\frac{-49-\sqrt{2501}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{2501}}{2*5}=\frac{-49+\sqrt{2501}}{10} $
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