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5x(x+96)=90
We move all terms to the left:
5x(x+96)-(90)=0
We multiply parentheses
5x^2+480x-90=0
a = 5; b = 480; c = -90;
Δ = b2-4ac
Δ = 4802-4·5·(-90)
Δ = 232200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{232200}=\sqrt{900*258}=\sqrt{900}*\sqrt{258}=30\sqrt{258}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(480)-30\sqrt{258}}{2*5}=\frac{-480-30\sqrt{258}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(480)+30\sqrt{258}}{2*5}=\frac{-480+30\sqrt{258}}{10} $
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