5x(x-1)+7x2=(6x-1)(2x+3)

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Solution for 5x(x-1)+7x2=(6x-1)(2x+3) equation: 



5x(x-1)+7x^2=(6x-1)(2x+3)

We move all terms to the left:

5x(x-1)+7x^2-((6x-1)(2x+3))=0

We multiply parentheses

7x^2+5x^2-5x-((6x-1)(2x+3))=0

We multiply parentheses ..

7x^2+5x^2-((+12x^2+18x-2x-3))-5x=0



We calculate terms in parentheses: -((+12x^2+18x-2x-3)), so:

(+12x^2+18x-2x-3)

We get rid of parentheses

12x^2+18x-2x-3

We add all the numbers together, and all the variables

12x^2+16x-3

Back to the equation:

-(12x^2+16x-3)



We add all the numbers together, and all the variables

12x^2-5x-(12x^2+16x-3)=0

We get rid of parentheses

12x^2-12x^2-5x-16x+3=0

We add all the numbers together, and all the variables

-21x+3=0

We move all terms containing x to the left, all other terms to the right

-21x=-3

x=-3/-21

x=1/7

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