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5x(x-1)-2(2x^2-7x)=-8
We move all terms to the left:
5x(x-1)-2(2x^2-7x)-(-8)=0
We add all the numbers together, and all the variables
5x(x-1)-2(2x^2-7x)+8=0
We multiply parentheses
5x^2-4x^2-5x+14x+8=0
We add all the numbers together, and all the variables
x^2+9x+8=0
a = 1; b = 9; c = +8;
Δ = b2-4ac
Δ = 92-4·1·8
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-7}{2*1}=\frac{-16}{2} =-8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+7}{2*1}=\frac{-2}{2} =-1 $
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