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5x(x-1)=2(x-4)-6
We move all terms to the left:
5x(x-1)-(2(x-4)-6)=0
We multiply parentheses
5x^2-5x-(2(x-4)-6)=0
We calculate terms in parentheses: -(2(x-4)-6), so:We get rid of parentheses
2(x-4)-6
We multiply parentheses
2x-8-6
We add all the numbers together, and all the variables
2x-14
Back to the equation:
-(2x-14)
5x^2-5x-2x+14=0
We add all the numbers together, and all the variables
5x^2-7x+14=0
a = 5; b = -7; c = +14;
Δ = b2-4ac
Δ = -72-4·5·14
Δ = -231
Delta is less than zero, so there is no solution for the equation
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