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5x(x-1)=40
We move all terms to the left:
5x(x-1)-(40)=0
We multiply parentheses
5x^2-5x-40=0
a = 5; b = -5; c = -40;
Δ = b2-4ac
Δ = -52-4·5·(-40)
Δ = 825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{825}=\sqrt{25*33}=\sqrt{25}*\sqrt{33}=5\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{33}}{2*5}=\frac{5-5\sqrt{33}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{33}}{2*5}=\frac{5+5\sqrt{33}}{10} $
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