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5x(x-3)+8=0
We multiply parentheses
5x^2-15x+8=0
a = 5; b = -15; c = +8;
Δ = b2-4ac
Δ = -152-4·5·8
Δ = 65
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{65}}{2*5}=\frac{15-\sqrt{65}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{65}}{2*5}=\frac{15+\sqrt{65}}{10} $
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