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5x(x-4)=-3x+44
We move all terms to the left:
5x(x-4)-(-3x+44)=0
We multiply parentheses
5x^2-20x-(-3x+44)=0
We get rid of parentheses
5x^2-20x+3x-44=0
We add all the numbers together, and all the variables
5x^2-17x-44=0
a = 5; b = -17; c = -44;
Δ = b2-4ac
Δ = -172-4·5·(-44)
Δ = 1169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{1169}}{2*5}=\frac{17-\sqrt{1169}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{1169}}{2*5}=\frac{17+\sqrt{1169}}{10} $
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