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5x(x-7)=2(x+14)
We move all terms to the left:
5x(x-7)-(2(x+14))=0
We multiply parentheses
5x^2-35x-(2(x+14))=0
We calculate terms in parentheses: -(2(x+14)), so:We get rid of parentheses
2(x+14)
We multiply parentheses
2x+28
Back to the equation:
-(2x+28)
5x^2-35x-2x-28=0
We add all the numbers together, and all the variables
5x^2-37x-28=0
a = 5; b = -37; c = -28;
Δ = b2-4ac
Δ = -372-4·5·(-28)
Δ = 1929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1929}}{2*5}=\frac{37-\sqrt{1929}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1929}}{2*5}=\frac{37+\sqrt{1929}}{10} $
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