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5x(x-8)=x+8
We move all terms to the left:
5x(x-8)-(x+8)=0
We multiply parentheses
5x^2-40x-(x+8)=0
We get rid of parentheses
5x^2-40x-x-8=0
We add all the numbers together, and all the variables
5x^2-41x-8=0
a = 5; b = -41; c = -8;
Δ = b2-4ac
Δ = -412-4·5·(-8)
Δ = 1841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{1841}}{2*5}=\frac{41-\sqrt{1841}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{1841}}{2*5}=\frac{41+\sqrt{1841}}{10} $
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