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5x(4x+1)=525
We move all terms to the left:
5x(4x+1)-(525)=0
We multiply parentheses
20x^2+5x-525=0
a = 20; b = 5; c = -525;
Δ = b2-4ac
Δ = 52-4·20·(-525)
Δ = 42025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{42025}=205$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-205}{2*20}=\frac{-210}{40} =-5+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+205}{2*20}=\frac{200}{40} =5 $
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