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5x*2x=340
We move all terms to the left:
5x*2x-(340)=0
Wy multiply elements
10x^2-340=0
a = 10; b = 0; c = -340;
Δ = b2-4ac
Δ = 02-4·10·(-340)
Δ = 13600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13600}=\sqrt{400*34}=\sqrt{400}*\sqrt{34}=20\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{34}}{2*10}=\frac{0-20\sqrt{34}}{20} =-\frac{20\sqrt{34}}{20} =-\sqrt{34} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{34}}{2*10}=\frac{0+20\sqrt{34}}{20} =\frac{20\sqrt{34}}{20} =\sqrt{34} $
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