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5x*4x=450
We move all terms to the left:
5x*4x-(450)=0
Wy multiply elements
20x^2-450=0
a = 20; b = 0; c = -450;
Δ = b2-4ac
Δ = 02-4·20·(-450)
Δ = 36000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{36000}=\sqrt{3600*10}=\sqrt{3600}*\sqrt{10}=60\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{10}}{2*20}=\frac{0-60\sqrt{10}}{40} =-\frac{60\sqrt{10}}{40} =-\frac{3\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{10}}{2*20}=\frac{0+60\sqrt{10}}{40} =\frac{60\sqrt{10}}{40} =\frac{3\sqrt{10}}{2} $
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