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5x*5x=60
We move all terms to the left:
5x*5x-(60)=0
Wy multiply elements
25x^2-60=0
a = 25; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·25·(-60)
Δ = 6000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6000}=\sqrt{400*15}=\sqrt{400}*\sqrt{15}=20\sqrt{15}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{15}}{2*25}=\frac{0-20\sqrt{15}}{50} =-\frac{20\sqrt{15}}{50} =-\frac{2\sqrt{15}}{5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{15}}{2*25}=\frac{0+20\sqrt{15}}{50} =\frac{20\sqrt{15}}{50} =\frac{2\sqrt{15}}{5} $
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