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5x+(-9)+3(x+3)=40
We move all terms to the left:
5x+(-9)+3(x+3)-(40)=0
determiningTheFunctionDomain 5x+3(x+3)-40+(-9)=0
We add all the numbers together, and all the variables
5x+3(x+3)-49=0
We multiply parentheses
5x+3x+9-49=0
We add all the numbers together, and all the variables
8x-40=0
We move all terms containing x to the left, all other terms to the right
8x=40
x=40/8
x=5
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