5x+(1/2x)=(1/2x)+10

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Solution for 5x+(1/2x)=(1/2x)+10 equation:



5x+(1/2x)=(1/2x)+10
We move all terms to the left:
5x+(1/2x)-((1/2x)+10)=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2x)+10)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
5x+(+1/2x)-((+1/2x)+10)=0
We get rid of parentheses
5x+1/2x-((+1/2x)+10)=0
We calculate fractions
5x+2x/4x^2+(-((+1*2x)/4x^2=0
We multiply all the terms by the denominator
5x*4x^2+2x+(-((+1*2x)=0
We calculate terms in parentheses: +(-((+1*2x), so:
-((+1*2x
We add all the numbers together, and all the variables
2x+5x*4x^2+(-((+1*2x)=0
Wy multiply elements
20x^3+2x+(-((+1*2x)=0
We calculate terms in parentheses: +(-((+1*2x), so:
-((+1*2x
We do not support expression: x^3

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