5x+(10-(x-2))=7x-(2x-5-(3x+7))

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Solution for 5x+(10-(x-2))=7x-(2x-5-(3x+7)) equation: 



5x+(10-(x-2))=7x-(2x-5-(3x+7))

We move all terms to the left:

5x+(10-(x-2))-(7x-(2x-5-(3x+7)))=0



We calculate terms in parentheses: +(10-(x-2)), so:

10-(x-2)

determiningTheFunctionDomain
-(x-2)+10

We get rid of parentheses

-x+2+10

We add all the numbers together, and all the variables

-1x+12

Back to the equation:

+(-1x+12)





We calculate terms in parentheses: -(7x-(2x-5-(3x+7))), so:

7x-(2x-5-(3x+7))



We calculate terms in parentheses: -(2x-5-(3x+7)), so:

2x-5-(3x+7)

determiningTheFunctionDomain
2x-(3x+7)-5

We get rid of parentheses

2x-3x-7-5

We add all the numbers together, and all the variables

-1x-12

Back to the equation:

-(-1x-12)



We get rid of parentheses

7x+1x+12

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We get rid of parentheses

5x-1x-8x+12-12=0

We add all the numbers together, and all the variables

-4x=0

x=0/-4

x=0

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