5x+(14x-3)=7(3x-2)+5

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Solution for 5x+(14x-3)=7(3x-2)+5 equation: 



5x+(14x-3)=7(3x-2)+5

We move all terms to the left:

5x+(14x-3)-(7(3x-2)+5)=0

We get rid of parentheses

5x+14x-(7(3x-2)+5)-3=0



We calculate terms in parentheses: -(7(3x-2)+5), so:

7(3x-2)+5

We multiply parentheses

21x-14+5

We add all the numbers together, and all the variables

21x-9

Back to the equation:

-(21x-9)



We add all the numbers together, and all the variables

19x-(21x-9)-3=0

We get rid of parentheses

19x-21x+9-3=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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