5x+(2x-3)+(x-1)5x=76

Solution for 5x+(2x-3)+(x-1)5x=76 equation:

5x+(2x-3)+(x-1)5x=76

We move all terms to the left:

5x+(2x-3)+(x-1)5x-(76)=0

We multiply parentheses

5x^2+5x+(2x-3)-5x-76=0

We get rid of parentheses

5x^2+5x+2x-5x-3-76=0

We add all the numbers together, and all the variables

5x^2+2x-79=0

a = 5; b = 2; c = -79;
Δ = b2-4ac
Δ = 22-4·5·(-79)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-12\sqrt{11}}{2*5}=\frac{-2-12\sqrt{11}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+12\sqrt{11}}{2*5}=\frac{-2+12\sqrt{11}}{10}
$