5x+(3+2x)=18+-(x+-1)

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Solution for 5x+(3+2x)=18+-(x+-1) equation: 



5x+(3+2x)=18+-(x+-1)

We move all terms to the left:

5x+(3+2x)-(18+-(x+-1))=0

We add all the numbers together, and all the variables

5x+(2x+3)-(18+-(x-1))=0

We use the square of the difference formula

5x+(2x+3)-(18-(x-1))=0

We get rid of parentheses

5x+2x-(18-(x-1))+3=0



We calculate terms in parentheses: -(18-(x-1)), so:

18-(x-1)

determiningTheFunctionDomain
-(x-1)+18

We get rid of parentheses

-x+1+18

We add all the numbers together, and all the variables

-1x+19

Back to the equation:

-(-1x+19)



We add all the numbers together, and all the variables

7x-(-1x+19)+3=0

We get rid of parentheses

7x+1x-19+3=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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