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5x+(3/2)x=950
We move all terms to the left:
5x+(3/2)x-(950)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x+(+3/2)x-950=0
We multiply parentheses
3x^2+5x-950=0
a = 3; b = 5; c = -950;
Δ = b2-4ac
Δ = 52-4·3·(-950)
Δ = 11425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11425}=\sqrt{25*457}=\sqrt{25}*\sqrt{457}=5\sqrt{457}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{457}}{2*3}=\frac{-5-5\sqrt{457}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{457}}{2*3}=\frac{-5+5\sqrt{457}}{6} $
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